//#region src/function/curryRight.d.ts
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function noArgFunc() {
 *  return 42;
 * }
 * const curriedNoArgFunc = curryRight(noArgFunc);
 * console.log(curriedNoArgFunc()); // 42
 */
declare function curryRight<R>(func: () => R): () => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function oneArgFunc(a: number) {
 *   return a * 2;
 * }
 * const curriedOneArgFunc = curryRight(oneArgFunc);
 * console.log(curriedOneArgFunc(5)); // 10
 */
declare function curryRight<P, R>(func: (p: P) => R): (p: P) => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function twoArgFunc(a: number, b: number) {
 *  return [a, b];
 * }
 * const curriedTwoArgFunc = curryRight(twoArgFunc);
 * const func = curriedTwoArgFunc(1);
 * console.log(func(2)); // [2, 1]
 */
declare function curryRight<P1, P2, R>(func: (p1: P1, p2: P2) => R): (p2: P2) => (p1: P1) => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function threeArgFunc(a: number, b: number, c: number) {
 *   return [a, b, c];
 * }
 * const curriedThreeArgFunc = curryRight(threeArgFunc);
 * const func = curriedThreeArgFunc(1);
 * const func2 = func(2);
 * console.log(func2(3)); // [3, 2, 1]
 */
declare function curryRight<P1, P2, P3, R>(func: (p1: P1, p2: P2, p3: P3) => R): (p3: P3) => (p2: P2) => (p1: P1) => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function fourArgFunc(a: number, b: number, c: number, d: number) {
 *  return [a, b, c, d];
 * }
 * const curriedFourArgFunc = curryRight(fourArgFunc);
 * const func = curriedFourArgFunc(1);
 * const func2 = func(2);
 * const func3 = func2(3);
 * console.log(func3(4)); // [4, 3, 2, 1]
 */
declare function curryRight<P1, P2, P3, P4, R>(func: (p1: P1, p2: P2, p3: P3, p4: P4) => R): (p4: P4) => (p3: P3) => (p2: P2) => (p1: P1) => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function fiveArgFunc(a: number, b: number, c: number, d: number, e: number) {
 *   return [a, b, c, d, e];
 * }
 * const curriedFiveArgFunc = curryRight(fiveArgFunc);
 * const func = curriedFiveArgFunc(1);
 * const func2 = func(2);
 * const func3 = func2(3);
 * const func4 = func3(4);
 * console.log(func4(5)); // [5, 4, 3, 2, 1]
 */
declare function curryRight<P1, P2, P3, P4, P5, R>(func: (p1: P1, p2: P2, p3: P3, p4: P4, p5: P5) => R): (p5: P5) => (p4: P4) => (p3: P3) => (p2: P2) => (p1: P1) => R;
/**
 * Curries a function, allowing it to be called with a single argument at a time and returning a new function that takes the next argument.
 * This process continues until all arguments have been provided, at which point the original function is called with all accumulated arguments.
 *
 * Unlike `curry`, this function curries the function from right to left.
 *
 * @param func - The function to curry.
 * @returns A curried function.
 *
 * @example
 * function sum(a: number, b: number, c: number) {
 *   return a + b + c;
 * }
 *
 * const curriedSum = curryRight(sum);
 *
 * // The parameter `c` should be given the value `10`.
 * const add10 = curriedSum(10);
 *
 * // The parameter `b` should be given the value `15`.
 * const add25 = add10(15);
 *
 * // The parameter `a` should be given the value `5`. The function 'sum' has received all its arguments and will now return a value.
 * const result = add25(5); // 30
 */
declare function curryRight(func: (...args: any[]) => any): (...args: any[]) => any;
//#endregion
export { curryRight };